Proof: Get Iterate Parent 18
Let's prove the following theorem:
if the following are true:
- expression state at time 18 = "iterate_args"
- arguments stack at time 18 = [ [ "Mexico", [ ] ], [ [ ], [ ] ] ]
- parent stack at time 18 = [ entry "MX": "Mexico", [
{"ES": "Estonia", "MX": "Mexico"}
, [ ] ] ]
then parent stack at time 19 = [ entry "MX": "Mexico", [ {"ES": "Estonia", "MX": "Mexico"}
, [ ] ] ]
Proof:
Given
1 | expression state at time 18 = "iterate_args" |
---|---|
2 | arguments stack at time 18 = [ [ "Mexico", [ ] ], [ [ ], [ ] ] ] |
3 | parent stack at time 18 = [ entry "MX": "Mexico", [ {"ES": "Estonia", "MX": "Mexico"} , [ ] ] ] |
# | Claim | Reason |
---|---|---|
1 | parent stack at time (18 + 1) = parent stack at time 18 | if expression state at time 18 = "iterate_args" and arguments stack at time 18 = [ [ "Mexico", [ ] ], [ [ ], [ ] ] ], then parent stack at time (18 + 1) = parent stack at time 18 |
2 | parent stack at time (18 + 1) = [ entry "MX": "Mexico", [ {"ES": "Estonia", "MX": "Mexico"} , [ ] ] ] |
if parent stack at time (18 + 1) = parent stack at time 18 and parent stack at time 18 = [ entry "MX": "Mexico", [ {"ES": "Estonia", "MX": "Mexico"} , [ ] ] ], then parent stack at time (18 + 1) = [ entry "MX": "Mexico", [ {"ES": "Estonia", "MX": "Mexico"} , [ ] ] ] |
3 | 18 + 1 = 19 | 18 + 1 = 19 |
4 | parent stack at time (18 + 1) = parent stack at time 19 | if 18 + 1 = 19, then parent stack at time (18 + 1) = parent stack at time 19 |
5 | parent stack at time 19 = [ entry "MX": "Mexico", [ {"ES": "Estonia", "MX": "Mexico"} , [ ] ] ] |
if parent stack at time (18 + 1) = parent stack at time 19 and parent stack at time (18 + 1) = [ entry "MX": "Mexico", [ {"ES": "Estonia", "MX": "Mexico"} , [ ] ] ], then parent stack at time 19 = [ entry "MX": "Mexico", [ {"ES": "Estonia", "MX": "Mexico"} , [ ] ] ] |
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