Proof: Get Iterate Parent 2

Let's prove the following theorem:

if the following are true:

expression state at time 2 = "iterate_args"
arguments stack at time 2 = [ [ entry "ES": "Estonia", [ entry "MX": "Mexico", [ ] ] ], [ ] ]
parent stack at time 2 = [ {"ES": "Estonia", "MX": "Mexico"}, [ ] ]

then parent stack at time 3 = [ {"ES": "Estonia", "MX": "Mexico"}, [ ] ]

Proof:

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Given

1	expression state at time 2 = "iterate_args"
2	arguments stack at time 2 = [ [ entry "ES": "Estonia", [ entry "MX": "Mexico", [ ] ] ], [ ] ]
3	parent stack at time 2 = [ `{"ES": "Estonia", "MX": "Mexico"}`, [ ] ]

Proof Table

#	Claim	Reason
1	parent stack at time (2 + 1) = parent stack at time 2	if expression state at time 2 = "iterate_args" and arguments stack at time 2 = [ [ entry "ES": "Estonia", [ entry "MX": "Mexico", [ ] ] ], [ ] ], then parent stack at time (2 + 1) = parent stack at time 2 (Do Iterage Args (4))
2	parent stack at time (2 + 1) = [ `{"ES": "Estonia", "MX": "Mexico"}`, [ ] ]	if parent stack at time (2 + 1) = parent stack at time 2 and parent stack at time 2 = [ `{"ES": "Estonia", "MX": "Mexico"}`, [ ] ], then parent stack at time (2 + 1) = [ `{"ES": "Estonia", "MX": "Mexico"}`, [ ] ] (Transitive Property of Equality)
3	2 + 1 = 3	2 + 1 = 3 (Fixed Value Statement)
4	parent stack at time (2 + 1) = parent stack at time 3	if 2 + 1 = 3, then parent stack at time (2 + 1) = parent stack at time 3 (Substitution)
5	parent stack at time 3 = [ `{"ES": "Estonia", "MX": "Mexico"}`, [ ] ]	if parent stack at time (2 + 1) = parent stack at time 3 and parent stack at time (2 + 1) = [ `{"ES": "Estonia", "MX": "Mexico"}`, [ ] ], then parent stack at time 3 = [ `{"ES": "Estonia", "MX": "Mexico"}`, [ ] ] (Transitive Property of Equality Variation 2)

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