Proof: Get Iterate State 18
Let's prove the following theorem:
if the following are true:
- expression state at time 18 = "iterate_args"
- arguments stack at time 18 = [ [ "Mexico", [ ] ], [ [ ], [ ] ] ]
then expression state at time 19 = "begin_expr"
Proof:
Given
1 | expression state at time 18 = "iterate_args" |
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2 | arguments stack at time 18 = [ [ "Mexico", [ ] ], [ [ ], [ ] ] ] |
# | Claim | Reason |
---|---|---|
1 | expression state at time (18 + 1) = "begin_expr" | if expression state at time 18 = "iterate_args" and arguments stack at time 18 = [ [ "Mexico", [ ] ], [ [ ], [ ] ] ], then expression state at time (18 + 1) = "begin_expr" |
2 | 18 + 1 = 19 | 18 + 1 = 19 |
3 | expression state at time (18 + 1) = expression state at time 19 | if 18 + 1 = 19, then expression state at time (18 + 1) = expression state at time 19 |
4 | expression state at time 19 = "begin_expr" | if expression state at time (18 + 1) = expression state at time 19 and expression state at time (18 + 1) = "begin_expr", then expression state at time 19 = "begin_expr" |
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