Proof: Get Iterate State 18

Let's prove the following theorem:

if the following are true:
  • expression state at time 18 = "iterate_args"
  • arguments stack at time 18 = [ [ "Mexico", [ ] ], [ [ ], [ ] ] ]

then expression state at time 19 = "begin_expr"

Proof:

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Given
1 expression state at time 18 = "iterate_args"
2 arguments stack at time 18 = [ [ "Mexico", [ ] ], [ [ ], [ ] ] ]
Proof Table
# Claim Reason
1 expression state at time (18 + 1) = "begin_expr" if expression state at time 18 = "iterate_args" and arguments stack at time 18 = [ [ "Mexico", [ ] ], [ [ ], [ ] ] ], then expression state at time (18 + 1) = "begin_expr"
2 18 + 1 = 19 18 + 1 = 19
3 expression state at time (18 + 1) = expression state at time 19 if 18 + 1 = 19, then expression state at time (18 + 1) = expression state at time 19
4 expression state at time 19 = "begin_expr" if expression state at time (18 + 1) = expression state at time 19 and expression state at time (18 + 1) = "begin_expr", then expression state at time 19 = "begin_expr"

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