Proof: Congruent Triangles
Let's prove the following theorem:
if distance AB = distance DE and distance BC = distance EF and distance AC = distance DF, then △ABC ≅ △DEF
Proof:
Proof Table
| # | Claim | Reason |
|---|---|---|
| 1 | distance CA = distance FD | if distance AC = distance DF, then distance CA = distance FD |
| 2 | △ABC ≅ △DEF | if distance AB = distance DE and distance BC = distance EF and distance CA = distance FD, then △ABC ≅ △DEF |
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