Proof: Congruent Triangles to Distance
Let's prove the following theorem:
if △ABC ≅ △DEF, then distance BA = distance ED
Proof:
Given
| 1 | △ABC ≅ △DEF |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | distance AB = distance DE | if △ABC ≅ △DEF, then distance AB = distance DE |
| 2 | distance BA = distance ED | if distance AB = distance DE, then distance BA = distance ED |
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