Proof: Distance Symmetry Example 2

Let's prove the following theorem:

Proof:

Proof Table

#	Claim	Reason
1	x ⋅ (distance BA) = (distance CD) ⋅ y	if x ⋅ (distance AB) = (distance CD) ⋅ y, then x ⋅ (distance BA) = (distance CD) ⋅ y (Distance Symmetry Example 5)
2	distance CD = distance DC	distance CD = distance DC (Distance Equality Property)
3	x ⋅ (distance BA) = (distance DC) ⋅ y	if x ⋅ (distance BA) = (distance CD) ⋅ y and distance CD = distance DC, then x ⋅ (distance BA) = (distance DC) ⋅ y (First Term Substitution)

Comments

Please log in to add comments