Proof: Parts of Line 2
Let's prove the following theorem:
if m∠ABC = 180, then (distance CA) + ((distance BC) ⋅ (-1)) = distance AB
Proof:
Given
1 | m∠ABC = 180 |
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# | Claim | Reason |
---|---|---|
1 | (distance AC) + ((distance BC) ⋅ (-1)) = distance AB | if m∠ABC = 180, then (distance AC) + ((distance BC) ⋅ (-1)) = distance AB |
2 | distance AC = distance CA | distance AC = distance CA |
3 | (distance CA) + ((distance BC) ⋅ (-1)) = distance AB | if (distance AC) + ((distance BC) ⋅ (-1)) = distance AB and distance AC = distance CA, then (distance CA) + ((distance BC) ⋅ (-1)) = distance AB |
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