Proof: Parts of Line 2

Let's prove the following theorem:

Proof:

Proof Table

#	Claim	Reason
1	(distance AC) + ((distance BC) ⋅ (-1)) = distance AB	if m∠ABC = 180, then (distance AC) + ((distance BC) ⋅ (-1)) = distance AB (Parts of Line)
2	distance AC = distance CA	distance AC = distance CA (Distance Equality Property)
3	(distance CA) + ((distance BC) ⋅ (-1)) = distance AB	if (distance AC) + ((distance BC) ⋅ (-1)) = distance AB and distance AC = distance CA, then (distance CA) + ((distance BC) ⋅ (-1)) = distance AB (Substitution 8)

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