Proof: Parts of Line 3
Let's prove the following theorem:
if m∠ABC = 180, then (distance CA) + ((distance CB) ⋅ (-1)) = distance BA
Proof:
Given
1 | m∠ABC = 180 |
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# | Claim | Reason |
---|---|---|
1 | m∠CBA = 180 | if m∠ABC = 180, then m∠CBA = 180 |
2 | distance CA = (distance CB) + (distance BA) | if m∠CBA = 180, then distance CA = (distance CB) + (distance BA) |
3 | (distance CA) + ((distance CB) ⋅ (-1)) = distance BA | if distance CA = (distance CB) + (distance BA), then (distance CA) + ((distance CB) ⋅ (-1)) = distance BA |
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