Proof: Sine
Let's prove the following theorem:
if ∠ABC is a right angle, then sine of (m∠BAC) = (distance CB) / (distance CA)
Proof:
Given
1 | ∠ABC is a right angle |
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# | Claim | Reason |
---|---|---|
1 | ∠CBA is a right angle | if ∠ABC is a right angle, then ∠CBA is a right angle |
2 | sine of (m∠BAC) = (distance CB) / (distance CA) | if ∠CBA is a right angle, then sine of (m∠BAC) = (distance CB) / (distance CA) |
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