Proof: Tangent 3
Let's prove the following theorem:
if ∠ABC is a right angle, then tangent of (m∠BAC) = (distance BC) / (distance AB)
Proof:
Given
| 1 | ∠ABC is a right angle |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | tangent of (m∠BAC) = (distance CB) / (distance BA) | if ∠ABC is a right angle, then tangent of (m∠BAC) = (distance CB) / (distance BA) |
| 2 | tangent of (m∠BAC) = (distance BC) / (distance AB) | if tangent of (m∠BAC) = (distance CB) / (distance BA), then tangent of (m∠BAC) = (distance BC) / (distance AB) |
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