Proof: Midpoint Theorem
Let's prove the following theorem:
if M is the midpoint of line XY, then distance XM = (distance XY) ⋅ (1 / 2)
    
    
Proof:
  
      
      Given
      
    
    
      
  
  
| 1 | M is the midpoint of line XY | 
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| # | Claim | Reason | 
|---|---|---|
| 1 | distance XM = distance MY | if M is the midpoint of line XY, then distance XM = distance MY | 
| 2 | (distance XM) + (distance MY) = distance XY | if M is the midpoint of line XY, then (distance XM) + (distance MY) = distance XY | 
| 3 | (distance XM) + (distance XM) = distance XY | if (distance XM) + (distance MY) = distance XY and distance XM = distance MY, then (distance XM) + (distance XM) = distance XY | 
| 4 | (distance XM) + (distance XM) = (distance XM) ⋅ 2 | (distance XM) + (distance XM) = (distance XM) ⋅ 2 | 
| 5 | (distance XM) ⋅ 2 = distance XY | if (distance XM) + (distance XM) = (distance XM) ⋅ 2 and (distance XM) + (distance XM) = distance XY, then (distance XM) ⋅ 2 = distance XY | 
| 6 | distance XM = (distance XY) ⋅ (1 / 2) | if (distance XM) ⋅ 2 = distance XY, then distance XM = (distance XY) ⋅ (1 / 2) | 
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