Geometry (Beta) / Chapter 5: Quadrilaterals / The Rhombus

Proof: If Diagonals Perpendicular Then Rhombus

Let's prove the following theorem:

if WXYZ is a parallelogram and ∠YPZ is a right angle and m∠WPY = 180 and m∠XPZ = 180, then WXYZ is a rhombus

Z W X Y P

Proof:

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Given
1 WXYZ is a parallelogram
2 YPZ is a right angle
3 m∠WPY = 180
4 m∠XPZ = 180
Proof Table
# Claim Reason
1 PYZ ≅ △PWX if WXYZ is a parallelogram and m∠WPY = 180 and m∠XPZ = 180, then △PYZ ≅ △PWX
2 distance YP = distance WP if △PYZ ≅ △PWX, then distance YP = distance WP
3 distance WP = distance YP if distance YP = distance WP, then distance WP = distance YP
4 WPZ and ∠ZPY are supplementary if m∠WPY = 180, then ∠WPZ and ∠ZPY are supplementary
5 (m∠WPZ) + (m∠YPZ) = 180 if ∠WPZ and ∠ZPY are supplementary, then (m∠WPZ) + (m∠YPZ) = 180
6 m∠YPZ = 90 if ∠YPZ is a right angle, then m∠YPZ = 90
7 (m∠WPZ) + 90 = 180 if (m∠WPZ) + (m∠YPZ) = 180 and m∠YPZ = 90, then (m∠WPZ) + 90 = 180
8 m∠WPZ = 90 if (m∠WPZ) + 90 = 180, then m∠WPZ = 90
9 m∠WPZ = m∠YPZ if m∠WPZ = 90 and m∠YPZ = 90, then m∠WPZ = m∠YPZ
10 distance PZ = distance PZ distance PZ = distance PZ
11 WPZ ≅ △YPZ if distance WP = distance YP and m∠WPZ = m∠YPZ and distance PZ = distance PZ, then △WPZ ≅ △YPZ
12 distance WZ = distance YZ if △WPZ ≅ △YPZ, then distance WZ = distance YZ
13 distance YZ = distance ZW if distance WZ = distance YZ, then distance YZ = distance ZW
14 WXYZ is a rhombus if WXYZ is a parallelogram and distance YZ = distance ZW, then WXYZ is a rhombus
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