Proof: Pythagorean Theorem 2

Let's prove the following theorem:

Proof:

Proof Table

#	Claim	Reason
1	((distance AB) ⋅ (distance AB)) + ((distance AC) ⋅ (distance AC)) = (distance BC) ⋅ (distance BC)	if ∠CAB is a right angle, then ((distance AB) ⋅ (distance AB)) + ((distance AC) ⋅ (distance AC)) = (distance BC) ⋅ (distance BC) (Pythagorean Theorem)
2	(distance BC) ⋅ (distance BC) = ((distance AB) ⋅ (distance AB)) + ((distance AC) ⋅ (distance AC))	if ((distance AB) ⋅ (distance AB)) + ((distance AC) ⋅ (distance AC)) = (distance BC) ⋅ (distance BC), then (distance BC) ⋅ (distance BC) = ((distance AB) ⋅ (distance AB)) + ((distance AC) ⋅ (distance AC)) (Symmetric Property of Equality)

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