Proof: Bisector SAS 2

Let's prove the following theorem:

Proof:

Proof Table

#	Claim	Reason
1	m∠ABX = m∠XBC	if ray BX bisects ∠ABC, then m∠ABX = m∠XBC (Angle Bisector Property)
2	m∠XBC = m∠CBX	m∠XBC = m∠CBX (Angle Symmetry Property)
3	m∠ABX = m∠CBX	if m∠ABX = m∠XBC and m∠XBC = m∠CBX, then m∠ABX = m∠CBX (Transitive Property of Equality)
4	distance BX = distance BX	distance BX = distance BX (Reflexive Property of Equality)
5	△ABX ≅ △CBX	if distance AB = distance CB and m∠ABX = m∠CBX and distance BX = distance BX, then △ABX ≅ △CBX (SAS Property)

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