Proof: Concurrent
Let's prove the following theorem:
if A is the midpoint of line XY and B is the midpoint of line ZX and PB ⊥ BX and PA ⊥ AY, then distance PZ = distance PY
Proof:
Given
1 | A is the midpoint of line XY |
---|---|
2 | B is the midpoint of line ZX |
3 | PB ⊥ BX |
4 | PA ⊥ AY |
# | Claim | Reason |
---|---|---|
1 | distance PX = distance PY | if PA ⊥ AY and A is the midpoint of line XY, then distance PX = distance PY |
2 | distance PZ = distance PX | if PB ⊥ BX and B is the midpoint of line ZX, then distance PZ = distance PX |
3 | distance PZ = distance PY | if distance PZ = distance PX and distance PX = distance PY, then distance PZ = distance PY |
Comments
Please log in to add comments