Proof: Multiplication Theorem
Let's prove the following theorem:
if not (c = 0), then (b ⋅ c) / c = b
    
    
    
    Proof:
  
      
      Given
      
    
    
      
  
  
| 1 | not (c = 0) | 
|---|
| # | Claim | Reason | 
|---|---|---|
| 1 | (b / c) ⋅ c = b | if not (c = 0), then (b / c) ⋅ c = b | 
| 2 | (b / c) ⋅ c = (b ⋅ c) / c | (b / c) ⋅ c = (b ⋅ c) / c | 
| 3 | (b ⋅ c) / c = b | if (b / c) ⋅ c = b and (b / c) ⋅ c = (b ⋅ c) / c, then (b ⋅ c) / c = b | 
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