Proof: Multiply by One
Let's prove the following theorem:
if not (c = 0), then (a ⋅ (1 / c)) ⋅ c = a
    
    
    
    Proof:
  
      
      Given
      
    
    
      
  
  
| 1 | not (c = 0) | 
|---|
| # | Claim | Reason | 
|---|---|---|
| 1 | (1 / c) ⋅ c = 1 | if not (c = 0), then (1 / c) ⋅ c = 1 | 
| 2 | (a ⋅ (1 / c)) ⋅ c = a ⋅ ((1 / c) ⋅ c) | (a ⋅ (1 / c)) ⋅ c = a ⋅ ((1 / c) ⋅ c) | 
| 3 | a ⋅ ((1 / c) ⋅ c) = a ⋅ 1 | if (1 / c) ⋅ c = 1, then a ⋅ ((1 / c) ⋅ c) = a ⋅ 1 | 
| 4 | a ⋅ 1 = a | a ⋅ 1 = a | 
| 5 | a ⋅ ((1 / c) ⋅ c) = a | if a ⋅ 1 = a and a ⋅ ((1 / c) ⋅ c) = a ⋅ 1, then a ⋅ ((1 / c) ⋅ c) = a | 
| 6 | (a ⋅ (1 / c)) ⋅ c = a | if a ⋅ ((1 / c) ⋅ c) = a and (a ⋅ (1 / c)) ⋅ c = a ⋅ ((1 / c) ⋅ c), then (a ⋅ (1 / c)) ⋅ c = a | 
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