Let's prove the following theorem:

(x^m) ⋅ (xⁿ) = x^{(m + n)}

Proof Table

#	Claim	Reason
1	x^{(m + n)} = (x^m) ⋅ (xⁿ)	x^{(m + n)} = (x^m) ⋅ (xⁿ) (Power By M and N)
2	(x^m) ⋅ (xⁿ) = x^{(m + n)}	if x^{(m + n)} = (x^m) ⋅ (xⁿ), then (x^m) ⋅ (xⁿ) = x^{(m + n)} (Symmetric Property of Equality)

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