Proof: Add Four
Let's prove the following theorem:
((a + a) + a) + a = a ⋅ 4
    
    
    
    Proof:
| # | Claim | Reason | 
|---|---|---|
| 1 | (a + a) + a = a ⋅ 3 | (a + a) + a = a ⋅ 3 | 
| 2 | ((a + a) + a) + a = (a ⋅ 3) + a | if (a + a) + a = a ⋅ 3, then ((a + a) + a) + a = (a ⋅ 3) + a | 
| 3 | a = a ⋅ 1 | a = a ⋅ 1 | 
| 4 | (a ⋅ 3) + a = (a ⋅ 3) + (a ⋅ 1) | if a = a ⋅ 1, then (a ⋅ 3) + a = (a ⋅ 3) + (a ⋅ 1) | 
| 5 | (a ⋅ 3) + (a ⋅ 1) = a ⋅ (3 + 1) | (a ⋅ 3) + (a ⋅ 1) = a ⋅ (3 + 1) | 
| 6 | 3 + 1 = 4 | 3 + 1 = 4 | 
| 7 | a ⋅ (3 + 1) = a ⋅ 4 | if 3 + 1 = 4, then a ⋅ (3 + 1) = a ⋅ 4 | 
| 8 | (a ⋅ 3) + (a ⋅ 1) = a ⋅ 4 | if a ⋅ (3 + 1) = a ⋅ 4 and (a ⋅ 3) + (a ⋅ 1) = a ⋅ (3 + 1), then (a ⋅ 3) + (a ⋅ 1) = a ⋅ 4 | 
| 9 | (a ⋅ 3) + a = a ⋅ 4 | if (a ⋅ 3) + (a ⋅ 1) = a ⋅ 4 and (a ⋅ 3) + a = (a ⋅ 3) + (a ⋅ 1), then (a ⋅ 3) + a = a ⋅ 4 | 
| 10 | ((a + a) + a) + a = a ⋅ 4 | if (a ⋅ 3) + a = a ⋅ 4 and ((a + a) + a) + a = (a ⋅ 3) + a, then ((a + a) + a) + a = a ⋅ 4 | 
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