Proof: Distributive Property Variation 2

Let's prove the following theorem:

Proof:

Proof Table

#	Claim	Reason
1	a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c)	a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c) (Distributive Property)
2	(b + c) ⋅ a = a ⋅ (b + c)	(b + c) ⋅ a = a ⋅ (b + c) (Commutative Property of Multiplication)
3	(b + c) ⋅ a = (a ⋅ b) + (a ⋅ c)	if a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c) and (b + c) ⋅ a = a ⋅ (b + c), then (b + c) ⋅ a = (a ⋅ b) + (a ⋅ c) (Transitive Property of Equality)

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