Proof: Distributive Property Variation 4

Let's prove the following theorem:

Proof:

Proof Table

#	Claim	Reason
1	a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c)	a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c) (Distributive Property)
2	(a ⋅ b) + (a ⋅ c) = a ⋅ (b + c)	if a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c), then (a ⋅ b) + (a ⋅ c) = a ⋅ (b + c) (Symmetric Property of Equality)

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