Proof: Distributive Property Variation 4

Let's prove the following theorem:

(a ⋅ b) + (a ⋅ c) = a ⋅ (b + c)

Proof:

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Proof Table
# Claim Reason
1 a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c) a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c)
2 (a ⋅ b) + (a ⋅ c) = a ⋅ (b + c) if a ⋅ (b + c) = (a ⋅ b) + (a ⋅ c), then (a ⋅ b) + (a ⋅ c) = a ⋅ (b + c)
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