Proof: Distributive Property 5

Let's prove the following theorem:

Proof:

Proof Table

#	Claim	Reason
1	(a + b) ⋅ c = (a ⋅ c) + (b ⋅ c)	(a + b) ⋅ c = (a ⋅ c) + (b ⋅ c) (Distributive Property Variation 3)
2	(a ⋅ c) + (b ⋅ c) = (a + b) ⋅ c	if (a + b) ⋅ c = (a ⋅ c) + (b ⋅ c), then (a ⋅ c) + (b ⋅ c) = (a + b) ⋅ c (Symmetric Property of Equality)

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