Proof: Algebra 16

Let's prove the following theorem:

(a ⋅ (s / 2)) / s = a / 2

Proof:

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Proof Table
# Claim Reason
1 s / 2 = s ⋅ (1 / 2) s / 2 = s ⋅ (1 / 2)
2 a ⋅ (s / 2) = a ⋅ (s ⋅ (1 / 2)) if s / 2 = s ⋅ (1 / 2), then a ⋅ (s / 2) = a ⋅ (s ⋅ (1 / 2))
3 a ⋅ (s ⋅ (1 / 2)) = (as) ⋅ (1 / 2) a ⋅ (s ⋅ (1 / 2)) = (as) ⋅ (1 / 2)
4 a ⋅ (s / 2) = (as) ⋅ (1 / 2) if a ⋅ (s / 2) = a ⋅ (s ⋅ (1 / 2)) and a ⋅ (s ⋅ (1 / 2)) = (as) ⋅ (1 / 2), then a ⋅ (s / 2) = (as) ⋅ (1 / 2)
5 (a ⋅ (s / 2)) / s = ((as) ⋅ (1 / 2)) / s if a ⋅ (s / 2) = (as) ⋅ (1 / 2), then (a ⋅ (s / 2)) / s = ((as) ⋅ (1 / 2)) / s
6 ((as) ⋅ (1 / 2)) / s = ((as) ⋅ (1 / 2)) ⋅ (1 / s) ((as) ⋅ (1 / 2)) / s = ((as) ⋅ (1 / 2)) ⋅ (1 / s)
7 ((as) ⋅ (1 / 2)) ⋅ (1 / s) = ((as) ⋅ (1 / s)) ⋅ (1 / 2) ((as) ⋅ (1 / 2)) ⋅ (1 / s) = ((as) ⋅ (1 / s)) ⋅ (1 / 2)
8 (as) ⋅ (1 / s) = a1 (as) ⋅ (1 / s) = a1
9 a1 = a a1 = a
10 (as) ⋅ (1 / s) = a if (as) ⋅ (1 / s) = a1 and a1 = a, then (as) ⋅ (1 / s) = a
11 ((as) ⋅ (1 / s)) ⋅ (1 / 2) = a ⋅ (1 / 2) if (as) ⋅ (1 / s) = a, then ((as) ⋅ (1 / s)) ⋅ (1 / 2) = a ⋅ (1 / 2)
12 ((as) ⋅ (1 / 2)) ⋅ (1 / s) = a ⋅ (1 / 2) if ((as) ⋅ (1 / 2)) ⋅ (1 / s) = ((as) ⋅ (1 / s)) ⋅ (1 / 2) and ((as) ⋅ (1 / s)) ⋅ (1 / 2) = a ⋅ (1 / 2), then ((as) ⋅ (1 / 2)) ⋅ (1 / s) = a ⋅ (1 / 2)
13 ((as) ⋅ (1 / 2)) / s = a ⋅ (1 / 2) if ((as) ⋅ (1 / 2)) / s = ((as) ⋅ (1 / 2)) ⋅ (1 / s) and ((as) ⋅ (1 / 2)) ⋅ (1 / s) = a ⋅ (1 / 2), then ((as) ⋅ (1 / 2)) / s = a ⋅ (1 / 2)
14 (a ⋅ (s / 2)) / s = a ⋅ (1 / 2) if (a ⋅ (s / 2)) / s = ((as) ⋅ (1 / 2)) / s and ((as) ⋅ (1 / 2)) / s = a ⋅ (1 / 2), then (a ⋅ (s / 2)) / s = a ⋅ (1 / 2)
15 a ⋅ (1 / 2) = a / 2 a ⋅ (1 / 2) = a / 2
16 (a ⋅ (s / 2)) / s = a / 2 if (a ⋅ (s / 2)) / s = a ⋅ (1 / 2) and a ⋅ (1 / 2) = a / 2, then (a ⋅ (s / 2)) / s = a / 2
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