Proof: Reordering Terms Theorem

Let's prove the following theorem:

(a ⋅ b) ⋅ c = (c ⋅ a) ⋅ b

Proof:

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Proof Table
# Claim Reason
1 (a ⋅ b) ⋅ c = (a ⋅ c) ⋅ b (a ⋅ b) ⋅ c = (a ⋅ c) ⋅ b
2 a ⋅ c = c ⋅ a a ⋅ c = c ⋅ a
3 (a ⋅ c) ⋅ b = (c ⋅ a) ⋅ b if a ⋅ c = c ⋅ a, then (a ⋅ c) ⋅ b = (c ⋅ a) ⋅ b
4 (a ⋅ b) ⋅ c = (c ⋅ a) ⋅ b if (a ⋅ b) ⋅ c = (a ⋅ c) ⋅ b and (a ⋅ c) ⋅ b = (c ⋅ a) ⋅ b, then (a ⋅ b) ⋅ c = (c ⋅ a) ⋅ b
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