Proof: Subtract Move Over
Let's prove the following theorem:
if a - b = c, then a = c + b
    
    
    
    Proof:
  
      
      Given
      
    
    
      
  
  
| 1 | a - b = c | 
|---|
| # | Claim | Reason | 
|---|---|---|
| 1 | (a - b) + b = c + b | if a - b = c, then (a - b) + b = c + b | 
| 2 | a - b = a + (b ⋅ (-1)) | a - b = a + (b ⋅ (-1)) | 
| 3 | (a - b) + b = (a + (b ⋅ (-1))) + b | if a - b = a + (b ⋅ (-1)), then (a - b) + b = (a + (b ⋅ (-1))) + b | 
| 4 | (a + (b ⋅ (-1))) + b = a + ((b ⋅ (-1)) + b) | (a + (b ⋅ (-1))) + b = a + ((b ⋅ (-1)) + b) | 
| 5 | (b ⋅ (-1)) + b = 0 | (b ⋅ (-1)) + b = 0 | 
| 6 | (a + (b ⋅ (-1))) + b = a + 0 | if (a + (b ⋅ (-1))) + b = a + ((b ⋅ (-1)) + b) and (b ⋅ (-1)) + b = 0, then (a + (b ⋅ (-1))) + b = a + 0 | 
| 7 | a + 0 = a | a + 0 = a | 
| 8 | (a + (b ⋅ (-1))) + b = a | if (a + (b ⋅ (-1))) + b = a + 0 and a + 0 = a, then (a + (b ⋅ (-1))) + b = a | 
| 9 | (a - b) + b = a | if (a - b) + b = (a + (b ⋅ (-1))) + b and (a + (b ⋅ (-1))) + b = a, then (a - b) + b = a | 
| 10 | a = c + b | if (a - b) + b = a and (a - b) + b = c + b, then a = c + b | 
Comments
Please log in to add comments