Proof: Pc 7
Let's prove the following theorem:
if the following are true:
- instruction #7 is
addi dst=4 src=4 imm=1
- the PC at time 7 = 7
then the PC at time 8 = 8
Instructions
Memory Cells |
---|
Program Counter | Time |
---|---|
0 | 0 |
LW Computer Simulator
Proof:
Given
1 | instruction #7 is addi dst=4 src=4 imm=1 |
---|---|
2 | the PC at time 7 = 7 |
# | Claim | Reason |
---|---|---|
1 | the PC at time (7 + 1) = 7 + 1 | if instruction #7 is addi dst=4 src=4 imm=1 and the PC at time 7 = 7, then the PC at time (7 + 1) = 7 + 1 |
2 | 7 + 1 = 8 | 7 + 1 = 8 |
3 | the PC at time (7 + 1) = the PC at time 8 | if 7 + 1 = 8, then the PC at time (7 + 1) = the PC at time 8 |
4 | the PC at time 8 = 8 | if the PC at time (7 + 1) = 7 + 1 and the PC at time (7 + 1) = the PC at time 8 and 7 + 1 = 8, then the PC at time 8 = 8 |
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