Proof: Congruent Triangles to Angles
Let's prove the following theorem:
if △ABC ≅ △DEF, then m∠BAC = m∠FDE
Proof:
Given
| 1 | △ABC ≅ △DEF |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | m∠CAB = m∠FDE | if △ABC ≅ △DEF, then m∠CAB = m∠FDE |
| 2 | m∠CAB = m∠BAC | m∠CAB = m∠BAC |
| 3 | m∠BAC = m∠FDE | if m∠CAB = m∠BAC and m∠CAB = m∠FDE, then m∠BAC = m∠FDE |
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