Proof: Square is Rhombus
Let's prove the following theorem:
if WXYZ is a square, then WXYZ is a rhombus
Proof:
Given
| 1 | WXYZ is a square |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | distance WX = distance XY | if WXYZ is a square, then distance WX = distance XY |
| 2 | distance XY = distance YZ | if WXYZ is a square, then distance XY = distance YZ |
| 3 | distance YZ = distance ZW | if WXYZ is a square, then distance YZ = distance ZW |
| 4 | WXYZ is a rhombus | if distance WX = distance XY and distance XY = distance YZ and distance YZ = distance ZW, then WXYZ is a rhombus |
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