Midpoint Sum
Commutative Property Example 2
Commutative Property Variation 1
Substitution 2
Substitution 8
Multiplicative Identity 2
Distributive Property 4
Multiplicative Property of Equality Variation 1
Addition Theorem
Transitive Property of Equality Variation 2
Double
Midpoint Distance 2
Substitution 11
Substitution 14
Midpoint Distance 2c
Transitive Property of Equality Variation 1
Divide Both Sides
Divide Both
Divide Substitute 2
Substitution 12
Substitution in Product
Multiply by One 2
Divide by 2
Collinear Angles Property 10
Collinear Angles Property 3
Transitive Property Application 2
Two Collinear Angles
Angle Symmetry Example 2
Distance Property 2
Distance Property 1
Collinear Then 180
Subtract Both Sides
Add Term to Both Sides 6
Subtract Both Sides 2
Add Term to Both Sides 7
Vertical Angles
Angle Addition Theorem
Collinear Angles Property 9
Collinear Angles B
Exterior Angle
Exterior Angle B
Collinear Angles Property 3 B
Collinear Angles Property 3 C
alternate interior angles then parallel
ParallelThenAIA
Parallel Then Aia 2
Vertical Angles C
Parallel Then Corresponding
Parallel Then Corresponding 2
Parallel Then Corresponding Short
Parallel Then Corresponding Short 3
Parallel Then Corresponding Short 3b
Parallel Transitive
Parallel Then Corresponding Short 2
Parallel Then Corresponding Short 4
Parallel Then Corresponding Short 4b
Angle Symmetry Example
Angle Symmetry 2
Similar Triangles
Divide Substitute
Multiplication Property 2
Multiply by One
Divide Numerators
Divide Numerators 2
If Sas Then Similar Triangles
Similar Corresponding Medians

Proof: Midpoint Distance 2c

Let's prove the following theorem:

if M is the midpoint of line AB, then (distance BM) ⋅ 2 = distance BA

B A M

Proof:

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Given
1 M is the midpoint of line AB
Proof Table
# Claim Reason
1 (distance MB) ⋅ 2 = distance AB if M is the midpoint of line AB, then (distance MB) ⋅ 2 = distance AB
2 distance MB = distance BM distance MB = distance BM
3 (distance BM) ⋅ 2 = distance AB if distance MB = distance BM and (distance MB) ⋅ 2 = distance AB, then (distance BM) ⋅ 2 = distance AB
4 distance AB = distance BA distance AB = distance BA
5 (distance BM) ⋅ 2 = distance BA if (distance BM) ⋅ 2 = distance AB and distance AB = distance BA, then (distance BM) ⋅ 2 = distance BA
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