Midpoint Sum
Commutative Property Example 2
Commutative Property Variation 1
Substitution 2
Substitution 8
Multiplicative Identity 2
Distributive Property 4
Multiplicative Property of Equality Variation 1
Addition Theorem
Transitive Property of Equality Variation 2
Double
Midpoint Distance 2
Substitution 11
Substitution 14
Midpoint Distance 2c
Transitive Property of Equality Variation 1
Divide Both Sides
Divide Both
Divide Substitute 2
Substitution 12
Substitution in Product
Multiply by One 2
Divide by 2
Collinear Angles Property 10
Collinear Angles Property 3
Transitive Property Application 2
Two Collinear Angles
Angle Symmetry Example 2
Distance Property 2
Distance Property 1
Collinear Then 180
Subtract Both Sides
Add Term to Both Sides 6
Subtract Both Sides 2
Add Term to Both Sides 7
Vertical Angles
Angle Addition Theorem
Collinear Angles Property 9
Collinear Angles B
Exterior Angle
Exterior Angle B
Collinear Angles Property 3 B
Collinear Angles Property 3 C
alternate interior angles then parallel
ParallelThenAIA
Parallel Then Aia 2
Vertical Angles C
Parallel Then Corresponding
Parallel Then Corresponding 2
Parallel Then Corresponding Short
Parallel Then Corresponding Short 3
Parallel Then Corresponding Short 3b
Parallel Transitive
Parallel Then Corresponding Short 2
Parallel Then Corresponding Short 4
Parallel Then Corresponding Short 4b
Angle Symmetry Example
Angle Symmetry 2
Similar Triangles
Divide Substitute
Multiplication Property 2
Multiply by One
Divide Numerators
Divide Numerators 2
If Sas Then Similar Triangles
Similar Corresponding Medians

Proof: Multiply by One

Let's prove the following theorem:

(a ⋅ (1 / c)) ⋅ c = a

Proof:

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Proof Table
# Claim Reason
1 (1 / c) ⋅ c = 1 (1 / c) ⋅ c = 1
2 (a ⋅ (1 / c)) ⋅ c = a ⋅ ((1 / c) ⋅ c) (a ⋅ (1 / c)) ⋅ c = a ⋅ ((1 / c) ⋅ c)
3 a ⋅ ((1 / c) ⋅ c) = a1 if (1 / c) ⋅ c = 1, then a ⋅ ((1 / c) ⋅ c) = a1
4 a1 = a a1 = a
5 a ⋅ ((1 / c) ⋅ c) = a if a ⋅ ((1 / c) ⋅ c) = a1 and a1 = a, then a ⋅ ((1 / c) ⋅ c) = a
6 (a ⋅ (1 / c)) ⋅ c = a if (a ⋅ (1 / c)) ⋅ c = a ⋅ ((1 / c) ⋅ c) and a ⋅ ((1 / c) ⋅ c) = a, then (a ⋅ (1 / c)) ⋅ c = a
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