Proof: Algebra 17

Let's prove the following theorem:

Proof:

Proof Table

#	Claim	Reason
1	s / s = 1	if not (s = 0), then s / s = 1 (Multiplicative Inverse Property)
2	s / s = s ⋅ (1 / s)	s / s = s ⋅ (1 / s) (Division is Multiplication by Inverse)
3	s ⋅ (1 / s) = 1	if s / s = s ⋅ (1 / s) and s / s = 1, then s ⋅ (1 / s) = 1 (Transitive Property of Equality Variation 2)

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