Proof: Add Inverse

Let's prove the following theorem:

Proof:

Proof Table

#	Claim	Reason
1	b ⋅ a = a ⋅ b	b ⋅ a = a ⋅ b (Commutative Property of Multiplication)
2	(b ⋅ a) + ((a ⋅ b) ⋅ (-1)) = 0	if b ⋅ a = a ⋅ b, then (b ⋅ a) + ((a ⋅ b) ⋅ (-1)) = 0 (Add Negative B)

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