Distance Property 2
Transitive Property of Equality Variation 2
Distance Property 1
Angle Symmetry Example 2
Collinear Angles Property 9
Transitive Property Application 2
Angles of an Isosceles Triangle
Angle Symmetry Example
Angle Symmetry 2
Isosceles Triangle B
Angle Symmetry B
Collinear Then 180
Subtract Both Sides
Add Term to Both Sides 6
Subtract Both Sides 2
Add Term to Both Sides 7
Transitive Property of Equality Variation 1
Vertical Angles
Angle Addition Theorem
Collinear Angles B
Exterior Angle
Exterior Angle B
Collinear Angles Property 10
Collinear Angles Property 3
Collinear Angles Property 3 B
Collinear Angles Property 3 C
alternate interior angles then parallel
ParallelThenAIA
Parallelthenaiashort
Commutative Property Example 2
Commutative Property Variation 1
Substitution 2
Substitution 8
Substitution Example 10
Substitute First Term
Triangles Sum to 180
Multiplicative Identity 2
Distributive Property 4
Multiplicative Property of Equality Variation 1
Addition Theorem
One Eighty 3
Divide Both Sides
Multiplicative Property of Equality Variation 2
Transitive Property of Equality Variation 3
Division is Commutative
Associative Property
Divide Each Side
Three Angles
Parallel Then Aia Short Mirror
Angle Symmetry 4
If Parallelogram Diagonal Then Congruent Triangles
If Parallelogram Then Sides Congruent
Sides of Rhombus Congruent 3
If Parallelogram Then Sides Congruent B
If Parallelogram Then Sides Congruent B2
Sides of Rhombus Congruent
Distance Property 4
Sides of Rhombus Congruent 2
Distance Property 5
Equilateral Sides 3
Rhombus Diagonal Equilateral Triangles

Proof: Distance Property 4

Let's prove the following theorem:

if distance AB = distance CD, then distance DC = distance BA

C D A B

Proof:

View as a tree | View dependent proofs | Try proving it

Given
1 distance AB = distance CD
Proof Table
# Claim Reason
1 distance AB = distance BA distance AB = distance BA
2 distance BA = distance CD if distance AB = distance BA and distance AB = distance CD, then distance BA = distance CD
3 distance CD = distance DC distance CD = distance DC
4 distance DC = distance BA if distance BA = distance CD and distance CD = distance DC, then distance DC = distance BA
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