Proof: Inverse Product Theorem
Let's prove the following theorem:
if not (a = 0), then (1 / a) ⋅ a = 1
Proof:
Given
1 | not (a = 0) |
---|
# | Claim | Reason |
---|---|---|
1 | a / a = 1 | if not (a = 0), then a / a = 1 |
2 | a / a = a ⋅ (1 / a) | a / a = a ⋅ (1 / a) |
3 | a ⋅ (1 / a) = (1 / a) ⋅ a | a ⋅ (1 / a) = (1 / a) ⋅ a |
4 | a / a = (1 / a) ⋅ a | if a / a = a ⋅ (1 / a) and a ⋅ (1 / a) = (1 / a) ⋅ a, then a / a = (1 / a) ⋅ a |
5 | (1 / a) ⋅ a = 1 | if a / a = (1 / a) ⋅ a and a / a = 1, then (1 / a) ⋅ a = 1 |
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