Proof: Swap Terms 2 and 3

Let's prove the following theorem:

(a ⋅ b) ⋅ c = (a ⋅ c) ⋅ b

Proof:

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Proof Table
# Claim Reason
1 (a ⋅ b) ⋅ c = a ⋅ (b ⋅ c) (a ⋅ b) ⋅ c = a ⋅ (b ⋅ c)
2 b ⋅ c = c ⋅ b b ⋅ c = c ⋅ b
3 a ⋅ (b ⋅ c) = a ⋅ (c ⋅ b) if b ⋅ c = c ⋅ b, then a ⋅ (b ⋅ c) = a ⋅ (c ⋅ b)
4 a ⋅ (c ⋅ b) = (a ⋅ c) ⋅ b a ⋅ (c ⋅ b) = (a ⋅ c) ⋅ b
5 (a ⋅ b) ⋅ c = (a ⋅ c) ⋅ b if a ⋅ (c ⋅ b) = (a ⋅ c) ⋅ b and a ⋅ (b ⋅ c) = a ⋅ (c ⋅ b) and (a ⋅ b) ⋅ c = a ⋅ (b ⋅ c), then (a ⋅ b) ⋅ c = (a ⋅ c) ⋅ b
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