Proof: Swap Terms 2 and 3

Let's prove the following theorem:

(ab) ⋅ c = (ac) ⋅ b

Proof:

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Proof Table
# Claim Reason
1 (ab) ⋅ c = a ⋅ (bc) (ab) ⋅ c = a ⋅ (bc)
2 bc = cb bc = cb
3 a ⋅ (bc) = a ⋅ (cb) if bc = cb, then a ⋅ (bc) = a ⋅ (cb)
4 a ⋅ (cb) = (ac) ⋅ b a ⋅ (cb) = (ac) ⋅ b
5 (ab) ⋅ c = (ac) ⋅ b if (ab) ⋅ c = a ⋅ (bc) and a ⋅ (bc) = a ⋅ (cb) and a ⋅ (cb) = (ac) ⋅ b, then (ab) ⋅ c = (ac) ⋅ b
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