Proof: Add Three
Let's prove the following theorem:
(a + a) + a = a ⋅ 3
Proof:
# | Claim | Reason |
---|---|---|
1 | a + a = a ⋅ 2 | a + a = a ⋅ 2 |
2 | a = a ⋅ 1 | a = a ⋅ 1 |
3 | (a + a) + a = (a ⋅ 2) + a | if a + a = a ⋅ 2, then (a + a) + a = (a ⋅ 2) + a |
4 | (a ⋅ 2) + a = (a ⋅ 2) + (a ⋅ 1) | if a = a ⋅ 1, then (a ⋅ 2) + a = (a ⋅ 2) + (a ⋅ 1) |
5 | (a ⋅ 2) + (a ⋅ 1) = a ⋅ (2 + 1) | (a ⋅ 2) + (a ⋅ 1) = a ⋅ (2 + 1) |
6 | (a ⋅ 2) + a = a ⋅ (2 + 1) | if (a ⋅ 2) + a = (a ⋅ 2) + (a ⋅ 1) and (a ⋅ 2) + (a ⋅ 1) = a ⋅ (2 + 1), then (a ⋅ 2) + a = a ⋅ (2 + 1) |
7 | 2 + 1 = 3 | 2 + 1 = 3 |
8 | a ⋅ (2 + 1) = a ⋅ 3 | if 2 + 1 = 3, then a ⋅ (2 + 1) = a ⋅ 3 |
9 | (a ⋅ 2) + a = a ⋅ 3 | if (a ⋅ 2) + a = a ⋅ (2 + 1) and a ⋅ (2 + 1) = a ⋅ 3, then (a ⋅ 2) + a = a ⋅ 3 |
10 | (a + a) + a = a ⋅ 3 | if (a + a) + a = (a ⋅ 2) + a and (a ⋅ 2) + a = a ⋅ 3, then (a + a) + a = a ⋅ 3 |
Comments
Please log in to add comments