Proof: Subtract Associative
Let's prove the following theorem:
(a + b) - c = a + (b - c)
Proof:
| # | Claim | Reason |
|---|---|---|
| 1 | (a + b) - c = (a + b) + (c ⋅ (-1)) | (a + b) - c = (a + b) + (c ⋅ (-1)) |
| 2 | (a + b) + (c ⋅ (-1)) = a + (b + (c ⋅ (-1))) | (a + b) + (c ⋅ (-1)) = a + (b + (c ⋅ (-1))) |
| 3 | b + (c ⋅ (-1)) = b - c | b + (c ⋅ (-1)) = b - c |
| 4 | a + (b + (c ⋅ (-1))) = a + (b - c) | if b + (c ⋅ (-1)) = b - c, then a + (b + (c ⋅ (-1))) = a + (b - c) |
| 5 | (a + b) + (c ⋅ (-1)) = a + (b - c) | if (a + b) + (c ⋅ (-1)) = a + (b + (c ⋅ (-1))) and a + (b + (c ⋅ (-1))) = a + (b - c), then (a + b) + (c ⋅ (-1)) = a + (b - c) |
| 6 | (a + b) - c = a + (b - c) | if (a + b) - c = (a + b) + (c ⋅ (-1)) and (a + b) + (c ⋅ (-1)) = a + (b - c), then (a + b) - c = a + (b - c) |
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