Proof: Angle Symmetry 2
Let's prove the following theorem:
if m∠ABC = m∠XYZ, then m∠CBA = m∠ZYX
    
    
Proof:
Proof Table
| # | Claim | Reason | 
|---|---|---|
| 1 | m∠ABC = m∠ZYX | if m∠ABC = m∠XYZ, then m∠ABC = m∠ZYX | 
| 2 | m∠ABC = m∠CBA | m∠ABC = m∠CBA | 
| 3 | m∠CBA = m∠ZYX | if m∠ABC = m∠CBA and m∠ABC = m∠ZYX, then m∠CBA = m∠ZYX | 
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