Proof: Multiply 2
Let's prove the following theorem:
((a + b) + a) + b = (a + b) ⋅ 2
Proof:
| # | Claim | Reason |
|---|---|---|
| 1 | ((a + b) + a) + b = (a + b) + (a + b) | ((a + b) + a) + b = (a + b) + (a + b) |
| 2 | (a + b) + (a + b) = (a + b) ⋅ 2 | (a + b) + (a + b) = (a + b) ⋅ 2 |
| 3 | ((a + b) + a) + b = (a + b) ⋅ 2 | if ((a + b) + a) + b = (a + b) + (a + b) and (a + b) + (a + b) = (a + b) ⋅ 2, then ((a + b) + a) + b = (a + b) ⋅ 2 |
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