Proof: Reorder Terms 6
Let's prove the following theorem:
if ((a + b) + a) + b = 360, then a + b = 180
Proof:
Given
| 1 | ((a + b) + a) + b = 360 |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | ((a + b) + a) + b = (a + b) ⋅ 2 | ((a + b) + a) + b = (a + b) ⋅ 2 |
| 2 | (a + b) ⋅ 2 = 360 | if ((a + b) + a) + b = (a + b) ⋅ 2 and ((a + b) + a) + b = 360, then (a + b) ⋅ 2 = 360 |
| 3 | a + b = 360 / 2 | if (a + b) ⋅ 2 = 360, then a + b = 360 / 2 |
| 4 | 360 / 2 = 180 | 360 / 2 = 180 |
| 5 | a + b = 180 | if a + b = 360 / 2 and 360 / 2 = 180, then a + b = 180 |
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